Published by:
CGP EDU Academic Team
Published on: September 12, 2026
The time period of a simple pendulum measured inside a stationary lift is found to be T. If the lift starts accelerating upwards with an acceleration g/3 , the time period is
Text Solution
Verified by ExpertsThe correct answer is:
B
\(T = 2 \pi \sqrt{\frac{l}{g}}\) and \(T' = 2 \pi \sqrt{\frac{l}{4g/3}}\)
\(\left[ \text{As} \quad g' = g + a = g + \frac{g}{3} = \frac{4g}{3} \right.\) ]
∴ ∴ T' = \(\frac{\sqrt{3}}{2}T\)
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